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Mailinglist:wwp@yahoogroups.com
Sender:Markus Altendorff
Date/Time:2005-Sep-28 17:23:00
Subject:Re: Does the image width have to be divisible by 2 to join correctly?

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wwp@yahoogroups.com: Re: Does the image width have to be divisible by 2 to join correctly? Markus Altendorff 2005-Sep-28 17:23:00
centreofengland wrote:
> --- In #removed#, Thomas Rauscher <#removed#> wrote:
> 
>>The problem is, that I currently use integer math for the cropping.
>>The solution is to make the horizontal tiles a divisor of the image
>>width.
>>MfG,
> 
>  Thomas.
> 
> Hi Thomas, So what you are saying is that lets say my jpg is 6550 
> pixels wide then I need to change the "Horizontal Tiles" value to 25?
> If so then I guess its best if my jpgs are a nice round figure rather 
> than somthing like 6569 pixels wide.
> 
> So the height of the jpg does not matter then?
> 

Once upon a time ;) the rule for QTVRs was that each tile 
(!) measure (in pixels) had to be divisible by 4 - of 
course, that was in the days of cylindrical-only panoramas, 
but i think it hasn't changed since then.
So, if you have 25 horizontal tiles, the value must be a 
multiple of (25*4) = 100 pixels since each tile must fit the 
rule. The vertical size must be a multiple of 4.

Note: At least i think so - with the advent of Mac OS X, 
even Apple's free tools learned how to re-scale and optimize 
these values all by themselves, so there's no real feedback 
left (earlier tools would simply come up with all kinds of 
error messages instead, and even with a helpful one like 
"nearest possible size 6144x768" or something).

-Markus

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